Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-4 Factoring Quadratic Expressions - Practice and Problem-Solving Exercises - Page 221: 37

Answer

$9(3p^2-p+2)$

Work Step by Step

Factoring the $GCF= 9 ,$ the given expression, $ 27p^2-9p+18 ,$ is equivalent to \begin{align*} 9(3p^2-p+2) \end{align*} Using the factoring of trinomials in the form $ax^2+bx+c,$ the expression above has $ac= 3(2)=6 $ and $b= -1 $ There are no two numbers with a product of $c$ and a sum of $b.$ Hence, the expression $ 9(3p^2-p+2) $ cannot be further factored.
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