Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 2 - Functions, Equations, and Graphs - 2-5 Using Linear Models - Practice and Problem-Solving Exercises - Page 98: 25

Answer

graph of $-\dfrac{2}{9}x-\dfrac{5}{9}y=10$:

Work Step by Step

The $x$-intercept is the value of $x$ when $y=0.$ Setting $y=0$ in the given equation, $ -\dfrac{2}{9}x-\dfrac{5}{9}y=10 ,$ results to \begin{align*} -\dfrac{2}{9}x-\dfrac{5}{9}(0)&=10 \\\\ -\dfrac{2}{9}x-0&=10 \\\\ -\dfrac{2}{9}x&=10 \\\\ \left(-\dfrac{9}{2} \right)\left(-\dfrac{2}{9}x\right)&=(10)\left(-\dfrac{9}{2} \right) \\\\ x&=-\dfrac{90}{2} \\\\ x&=-45 .\end{align*} Hence, the $x$-intercept is $( -45,0 )$. The $y$-intercept is the value of $y$ when $x=0.$ Setting $x=0$ in the given equation results to \begin{align*} -\dfrac{2}{9}(0)-\dfrac{5}{9}y&=10 \\\\ 0-\dfrac{5}{9}y&=10 \\\\ -\dfrac{5}{9}y&=10 \\\\ \left(-\dfrac{9}{5}\right)\left(-\dfrac{5}{9}y\right)&=(10)\left(-\dfrac{9}{5}\right) \\\\ y&=-\dfrac{90}{5} \\\\ y&=-18 .\end{align*} Hence, the $y$-intercept is $( 0,-18 )$. By connecting the two intercepts, the graph of the given line is determined.
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