Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 2 - Functions, Equations, and Graphs - 2-5 Using Linear Models - Practice and Problem-Solving Exercises - Page 98: 23

Answer

$-7$

Work Step by Step

Substituting the point $(a,-3)$ into the given equation, $ (y-1)=\dfrac{2}{3}(x+1) ,$ and then solving for $a$ result to \begin{align*} (-3-1)&=\dfrac{2}{3}(a+1) \\\\ -4&=\dfrac{2}{3}(a+1) \\\\ 3(-4)&=\left(\dfrac{2}{3}(a+1)\right)3 \\\\ 3(-4)&=2(a+1) \\\\ -12&=2a+2 \\\\ -12-2&=2a \\\\ -14&=2a \\\\ -\dfrac{14}{2}&=\dfrac{2a}{2} \\\\ -7&=a .\end{align*} Hence, the value of $a$ is $ -7 $
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