Answer
$\dfrac{6!}{4!\text{ }2!}=15$
Work Step by Step
Using $n!=n(n-1)(n-2)...(3)(2)(1),$ the value of the given expression, $
\dfrac{6!}{4!\text{ }2!}
,$ is
\begin{align*}\require{cancel}
&
\dfrac{6(5)(4!)}{4!\text{ }2!}
\\\\&=
\dfrac{6(5)(\cancel{4!})}{\cancel{4!}\text{ }2!}
\\\\&=
\dfrac{6(5)}{2!}
\\\\&=
\dfrac{6(5)}{2(1)}
\\\\&=
\dfrac{\cancel6^3(5)}{\cancel2(1)}
\\\\&=
3(5)
\\&=
15
.\end{align*}
Hence, $
\dfrac{6!}{4!\text{ }2!}=15
$.
