Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - Mid-Chapter Quiz - Page 710: 10

Answer

$_4P_4=24$

Work Step by Step

Using $ _nP_r=\dfrac{n!}{(n-r)!} $ or the Permutation of $n$ taken $r,$ the given expression, $ _4P_4 ,$ is equivalent to \begin{align*}\require{cancel} & \dfrac{4!}{(4-4)!} \\\\&= \dfrac{4!}{0!} \\\\&= \dfrac{4!}{1} &\text{(use }0!=1) \\\\&= 4! \\&= 4(3)(2)(1) \\&= 24 .\end{align*} Hence, $ _4P_4=24 .$
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