Answer
$\dfrac{3}{5}$
Work Step by Step
The sample space has a total of $10$ elements. The numbers less than $7$ are $\{5,6\}$. The numbers greater than $10$ are $\{11,12,13,14\}$. All in all, there are $6$ events that satisfy the condition "less than $7$ or greater than $10."$ Hence,
\begin{align*}\require{cancel}
P(\text{less than $7$ or greater than $10$})&=
\dfrac{6}{10}
\\\\&=
\dfrac{\cancel6^3}{\cancel10^5}
&\text{(divide by $2$)}
\\\\&=
\dfrac{3}{5}
.\end{align*}
