Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-3 Probability of Multiple Events - Practice and Problem-Solving Exercises - Page 691: 16

Answer

$\dfrac{2}{7}$ or approximately $28.6$%

Work Step by Step

Use the formula for independent events to find the probability of the events both happening. The formula is $P(Q$ $and$ $R)=P(Q)$ $\times$ $P(R)$. We are given $P(Q)=\dfrac{1}{3}$ and $P(R)=\dfrac{6}{7}$. Plug the values into the formula: $P(Q$ $and$ $R)$ = $\dfrac{1}{3}$ $\times$ $\dfrac{6}{7}$ $P(Q$ $and$ $R)$ = $\dfrac{6}{21}$ $P(Q$ $and$ $R)$ = $\dfrac{2}{7}$ $P(Q$ $and$ $R)$ $\approx$ $28.6$%
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