Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-1 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 680: 65



Work Step by Step

Factoring the $GCF=3,$ the given expression, $ 3x^2-75 ,$ is equivalent to \begin{align*}\require{cancel} & 3(x^2-25) .\end{align*} Using the factoring of the difference of $2$ squares which is given by $a^2-b^2=(a+b)(a-b),$ the expression above is equivalent to \begin{align*} & 3[(x)^2-(5)^2] \\&= 3[(x+5)(x-5)] \\&= 3(x+5)(x-5) .\end{align*} The factored form of the given expression is $ 3(x+5)(x-5) .$
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