Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-1 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 680: 54

Answer

$a$. $8,568 $ $b$. $658,008$

Work Step by Step

$a$. Total respondents = $40$ The graph shows that $45\%$ of the respondents squeeze from the middle. Thus, the number of respondents who prefer to squeeze from middle = $45\%(40) = (0.45)(40) = 18$ Hence, the number of possible combinations of $5$ persons out of $18$ is: $_{18}C_5= \dfrac{18!}{5!(18-5)!}$ $_{18}C_5= \dfrac{6402373705728000}{120(6227020800)}$ $_{18}C_5= 8,568$ $b$. Number of combinations of $5$ persons out of $40$ is: $_{40}C_5= \dfrac{40!}{5!(40-5)!}$ $_{40}C_5= \dfrac{40!}{5!(35)!}$ $_{40}C_5= \dfrac{40(39)(38)(37)(36)(35!)}{5!35!}\\ _{40}C_5= 658,008$
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