Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 11 - Probability and Statistics - 11-1 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 680: 68

Answer

$210$

Work Step by Step

Cancelling the common factors between the numerator and the denominator, the given expression, $ \dfrac{7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1}{4\cdot3\cdot2\cdot1} ,$ is equivalent to \begin{align*}\require{cancel} & \dfrac{7\cdot6\cdot5\cdot\cancel{4\cdot3\cdot2\cdot1}}{\cancel{4\cdot3\cdot2\cdot1}} \\\\&= 7(6)(5) \\&= 210 .\end{align*} Hence, the given expression simplifies to $ 210 .$
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