Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 10 - Quadratic Relations and Conic Sections - 10-3 Circles - Practice and Problem-Solving Exercises - Page 634: 9

Answer

$(x-2)^2 + (y-3)^2 = 20.25$

Work Step by Step

The standard equation of a circle with center $(h,k)$ and radius $r$ is $$(x-h)^2+(y-k)^2=r^2$$ Substitute $(h,k)=(2,3)$ and $r = 4.5$ to obtain the circle's equation: $$(x-2)^2+(y-3)^2=4.5^2$$ $$(x-2)^2 + (y-3)^2 = 20.25$$
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