Answer
$(x-1)^2 + (y+3)^2 = 100$
Work Step by Step
The standard equation of a circle with center $(h,k)$ and radius $r$ is:
$$(x-h)^2+(y-k)^2=r^2$$
Substitute $(h,k)=(1,-3)$ and $ r = 10$ and we have:
$$(x-1)^2 + (y-(-3))^2 = 10^2$$ $$(x-1)^2 + (y+3)^2 = 100$$
