Answer
$(x+6)^2 + (y-10)^2 = 1$
Work Step by Step
The standard equation of a circle with center $(h,k)$ and radius $r$ is:
$$(x-h)^2+(y-k)^2=r^2$$
Substitute $(h,k)=(-6,10)$ and $ r = 1$ and we have:
$$(x+6)^2 + (y-10)^2 = 1$$
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 10 - Quadratic Relations and Conic Sections - 10-3 Circles - Practice and Problem-Solving Exercises - Page 634: 10
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
