Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Chapter Review - Page 671: 29


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Work Step by Step

A hyperbola with foci $(0, \pm 5)$ and vertices on the y-axis: Since the vertices are at $(0,\pm 2) \rightarrow a=2$. The foci are at $(0,\pm 5) \rightarrow ae=5$. Rewrite the equation in standard form: $\frac{x^2}{5^2-2^2}-\frac{y^2}{2^2}=1\\\frac{x^2}{21}-\frac{y^2}{4}=-1\\\frac{y^2}{4}-\frac{x^2}{21}=1$
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