Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Chapter Review - Page 671: 25

Answer

See below

Work Step by Step

If the vertex of an ellipse is at $(\pm a,0)$ and the vertex is at $(0,\pm b)$, then the equation of the ellipse is $\frac{x^2}{a^2(1-e^2)}+\frac{y^2}{b^2}=1$ Hence here $a=8,ae=5$, and the equation is: $\frac{x^2}{64-25}+\frac{y^2}{64}=1\\\frac{x^2}{39}+\frac{y^2}{64}=1$
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