Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Chapter Review - Page 671: 27


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Work Step by Step

Given $4x^2-16y^2=64$ Rewrite the equation in standard form: $\frac{x^2}{16}-\frac{y^2}{4}=1$ Note that $a=4, b=2$. The transverse axis is horizontal. The vertices are at $(\pm 4, 0$). The foci are at $(\pm 2\sqrt 5, 0)$. The asymptotes are $y=\pm \frac{1}{2}x$. Draw the hyperbola.
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