#### Answer

See below

#### Work Step by Step

Given $4x^2-16y^2=64$
Rewrite the equation in standard form: $\frac{x^2}{16}-\frac{y^2}{4}=1$
Note that $a=4, b=2$. The transverse axis is horizontal. The vertices are at $(\pm 4, 0$).
The foci are at $(\pm 2\sqrt 5, 0)$. The asymptotes are $y=\pm \frac{1}{2}x$.
Draw the hyperbola.