Answer
See below
Work Step by Step
The equation in standard form: $y^2=16x$
Identify the focus, directrix, and axis of symmetry. The equation has the form $y^2=4px$ where $p=4 $. The focus is $(4, 0)$. The directrix is $x =-p=-4$. Because $y$ is squared, the axis of symmetry is the x-axis.
Find some values:
$x=1 \rightarrow y=\pm 4\\x=2 \rightarrow y=\pm 5.66\\x=3 \rightarrow y=\pm 6.93\\x=4 \rightarrow y=\pm 8\\x=5 \rightarrow y=\pm 8.94$