Answer
See below
Work Step by Step
The equation in standard form: $-5x+\frac{1}{3}y^2=0\\x^2=-\frac{12}{5}y$
Identify the focus, directrix, and axis of symmetry. The equation has the form $y^2=4px$ where $p=\frac{15}{4}$. The focus is $(\frac{15}{4},0)$. The directrix is $x =-p=\frac{-15}{4}$. Because $y$ is squared, the axis of symmetry is the x-axis.
Find some values and plot points:
$x=1 \rightarrow y=\pm 3.87\\x=2 \rightarrow y=\pm 5.48\\x=3 \rightarrow y=\pm 6.71\\x=4 \rightarrow y=\pm 7.75\\x=5 \rightarrow y=\pm 8.66$
