#### Answer

$$\frac{1}{16}$$

#### Work Step by Step

Simplifying the equation, we find:
$$\frac{\left(x^2+15x+36\right)}{2x^2-18}\times \frac{x-3}{\left(8x+96\right)}\\ \frac{\left(x+12\right)\left(x-3\right)}{2\left(x-3\right)\left(8x+96\right)}
\\ \frac{x+12}{16\left(x+12\right)}\\ \frac{1}{16}$$