Chapter 9 Quadratic Relations and Conic Sections - 9.2 Graph and Write Equations of Parabolas - 9.2 Exercises - Mixed Review - Page 625: 66

$$\frac{1}{16}$$

Simplifying the equation, we find: $$\frac{\left(x^2+15x+36\right)}{2x^2-18}\times \frac{x-3}{\left(8x+96\right)}\\ \frac{\left(x+12\right)\left(x-3\right)}{2\left(x-3\right)\left(8x+96\right)} \\ \frac{x+12}{16\left(x+12\right)}\\ \frac{1}{16}$$