## Algebra 2 (1st Edition)

$$-\frac{4x^5}{3y^{2}}$$
Simplifying the equation, we find: $$\frac{4x^7y^3}{3x^2y^5}\\- \frac{4x^5}{3y^{5-3}}\\ -\frac{4x^5}{3y^{2}}$$