## Algebra 2 (1st Edition)

According to the exercise $y=\frac{a}{x}$ for some constant $a$. Then plugging in the values given: $\frac{5}{8}=\frac{a}{\frac{3}{4}}\\a=\frac{15}{32}$, hence $y=\frac{15}{32}\frac{1}{x}$. Hence here: $y=\frac{15}{32}\frac{1}{4}=\frac{15}{128}$.