Algebra 2 (1st Edition)

$$\frac{x-3}{\left(x+8\right)\left(x+5\right)}$$
Performing the given operation and then factoring and combining like terms to simplify, we find: $$\frac{\left(x^2-8x+15\right)\left(x+4\right)}{\left(x^2+12x+32\right)\left(x^2-25\right)}\\ \frac{\left(x-3\right)\left(x-5\right)}{\left(x+8\right)\left(x+5\right)\left(x-5\right)}\\ \frac{x-3}{\left(x+8\right)\left(x+5\right)}$$