#### Answer

6

#### Work Step by Step

We use cross multiplication to solve. Doing this, we find: $$\left(x-2\right)\left(x+4\right)=\left(x-1\right)\left(x+2\right)\\ x^2+2x-8=x^2+x-2 \\ x=6$$ Checking, we see that the solution is not extraneous.

Published by
McDougal Littell

ISBN 10:
0618595414

ISBN 13:
978-0-61859-541-9

6

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.