Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 8 Rational Functions - 8.6 Solve Rational Equations - 8.6 Exercises - Quiz for Lessons 8.4-8.6 - Page 595: 13



Work Step by Step

Multiplying both sides by $x(x+3)$ we get: $(x-1)(x+3)+(2x-1)x=(x+6)x\\x^2+2x-3+2x^2-x=x^2+6x\\2x^2-5x-3=0\\(x-3)(2x+1)=0$ Thus $x=3$ or $x=-0.5$, and $x=-.5$ is extraneous.
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