Answer
$x=3$
Work Step by Step
Multiplying both sides by $x(x+3)$ we get: $(x-1)(x+3)+(2x-1)x=(x+6)x\\x^2+2x-3+2x^2-x=x^2+6x\\2x^2-5x-3=0\\(x-3)(2x+1)=0$
Thus $x=3$ or $x=-0.5$, and $x=-.5$ is extraneous.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 8 Rational Functions - 8.6 Solve Rational Equations - 8.6 Exercises - Quiz for Lessons 8.4-8.6 - Page 595: 13
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