Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 8 Rational Functions - 8.6 Solve Rational Equations - 8.6 Exercises - Quiz for Lessons 8.4-8.6 - Page 595: 1



Work Step by Step

Multiplying the two expressions and then cancelling out like terms and factors in the numerator and the denominator, we find: $$\frac{x^2-2x-24}{x^2+3x-10}\cdot \frac{3\left(x-2\right)}{x\left(x+4\right)}\\ \frac{3\left(x+4\right)\left(x-6\right)\left(x-2\right)}{\left(x^2+3x-10\right)x\left(x+4\right)} \\ \frac{3\left(x+4\right)\left(x-6\right)\left(x-2\right)}{\left(x^2+3x-10\right)x\left(x+4\right)}\\ \frac{3\left(x+4\right)\left(x-6\right)\left(x-2\right)}{x\left(x-2\right)\left(x+5\right)\left(x+4\right)}\\ \frac{3\left(x-6\right)}{x\left(x+5\right)}$$
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