Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 8 Rational Functions - 8.6 Solve Rational Equations - 8.6 Exercises - Quiz for Lessons 8.4-8.6 - Page 595: 12



Work Step by Step

We solve the equation using cross multiplication. Doing this, we find: $$\frac{x-3}{x+2}=\frac{x-1}{3x-1} \\ \left(x-3\right)\left(3x-1\right)=\left(x+2\right)\left(x-1\right) \\ x=5,\:x=\frac{1}{2}$$ Checking, we see that the solution is not extraneous.
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