Answer
$$\frac{\left(x-4\right)^2\left(x+9\right)}{x+7}$$
Work Step by Step
Using the rules of exponents and cancelling common factors in the numerator and the denominator, we find:
$$\frac{\left(x^2+5x-36\right)\left(x^2-11x+28\right)}{x^2-49}\\ \frac{\left(x-4\right)^2\left(x+9\right)\left(x-7\right)}{\left(x+7\right)\left(x-7\right)}\\ \frac{\left(x-4\right)^2\left(x+9\right)}{x+7}$$
