## Algebra 2 (1st Edition)

$$\frac{y^2}{3x}$$
Using the rules of exponents and cancelling common factors in the numerator and the denominator, we find: $$\frac{5x}{y}\times \frac{y^3}{15x^2}\\ \frac{5xy^3}{y\times \:15x^2}\\ \frac{xy^3}{3x^2y}\\ \frac{y^2}{3x}$$