Answer
$$\left(x-3\right)\left(x+3\right)$$
Work Step by Step
Using the rules of exponents and cancelling common factors in the numerator and the denominator, we find:
$$\frac{x\left(x-3\right)\left(x+3\right)\left(x-2\right)}{\left(x-2\right)x}\\ \frac{\left(x-3\right)\left(x+3\right)\left(x-2\right)}{x-2}\\ \left(x-3\right)\left(x+3\right)$$
