Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - Chapter Test - Page 543: 26


$y=2.954\cdot x^{0.907}$

Work Step by Step

Let $y=ax^b$. Then our equations are: $8=a3^b$ and $15=a6^b$. If we divide the second equation by the first one we get: $1.875=2^b=\\b=\ln_{2}{1.875}\approx0.907$. Then $8=a3^{0.907}\\a=\frac{8}{3^{0.907}}\approx2.954$. Thus $y=2.954\cdot x^{0.907}$
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