Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - Chapter Test - Page 543: 20


$$ \frac{log23}{log6} \approx 1.750 $$

Work Step by Step

Using the change of base formula, we find: $$log_6(23) = \frac{log23}{log6}$$
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