Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - Chapter Test - Page 543: 25



Work Step by Step

Let $y=ab^x$. Then our equations are: $48=ab^{-1}$ and $6=ab^2$. If we divide the second equation by the first one we get: $0.125=b^3$, thus: $b=0.5$. Then $6=a\cdot(0.5)^2=0.25a\\a=24$. Thus $y=24\cdot0.5^x$
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