## Algebra 2 (1st Edition)

$y=28\cdot x^{0.752}$
Let $y=ax^b$. Then two of our equations are: $28=a1^b$ and $64=a3^b$. Then from the first one: $a=28$ Then $64=28\cdot3^b\\\frac{64}{28}=3^b\\b=\log_3{\frac{64}{28}}\approx0.752$ Thus $y=28\cdot x^{0.752}$