Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - Chapter Review - Page 542: 38


$y=28\cdot x^{0.752}$

Work Step by Step

Let $y=ax^b$. Then two of our equations are: $28=a1^b$ and $64=a3^b$. Then from the first one: $a=28$ Then $64=28\cdot3^b\\\frac{64}{28}=3^b\\b=\log_3{\frac{64}{28}}\approx0.752$ Thus $y=28\cdot x^{0.752}$
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