Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - Chapter Review - Page 542: 35



Work Step by Step

Let $y=ab^x$. Then our equations are: $8=ab^3$ and $2=ab^5$. If we divide the second equation by the first one we get: $0.25=b^2$. Thus because $b$ is positive: $b=0.5$. Then $8=a(0.5)^3=0.125a\\a=64$. Thus $y=64\cdot(0.5)^x$
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