Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - Chapter Review - Page 542: 37



Work Step by Step

Let $y=ab^x$. Then our equations are: $9=ab^{2}$ and $324=ab^{4}$. If we divide the second equation by the first one we get: $36=b^2$. Thus because $b$ is positive: $b=6$. Then $9=a(6)^2=36a\\a=0.25$. Thus $y=0.25\cdot(6)^x$
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