Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.5 Apply Properties of Logarithms - 7.5 Exercises - Mixed Review - Page 513: 83



Work Step by Step

Simplifying using the rules of radicals, we find: $$\left(x+2\right)^2=\left(\sqrt{9x+28}\right)^2 \\ x^2+4x+4=9x+28 \\ x=8,\:x=-3$$ -3 is not a valid solution, so: $$x=8$$
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