Answer
8
Work Step by Step
Simplifying using the rules of radicals, we find:
$$\left(x+2\right)^2=\left(\sqrt{9x+28}\right)^2 \\ x^2+4x+4=9x+28 \\ x=8,\:x=-3$$
-3 is not a valid solution, so:
$$x=8$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.5 Apply Properties of Logarithms - 7.5 Exercises - Mixed Review - Page 513: 83
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