Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.5 Apply Properties of Logarithms - 7.5 Exercises - Mixed Review - Page 513: 82

Answer

$$x=5,\:x=2$$

Work Step by Step

Simplifying using the rules of radicals, we find: $$\left(\sqrt{x-1}\right)^2=\left(x-3\right)^2 \\ x-1=x^2-6x+9 \\ x=5,\:x=2$$
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