Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.5 Apply Properties of Logarithms - 7.5 Exercises - Mixed Review - Page 513: 80

Answer

$$x=10$$

Work Step by Step

Simplifying using the rules of radicals, we find: $$\left(\sqrt{x+6}\right)^2=\left(\sqrt{3x-14}\right)^2 \\ x+6=3x-14 \\ x=10$$
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