## Algebra 2 (1st Edition)

$$2\left(x-1\right)^2+5$$
Completing the square to put the equation in vertex form, we find: $$2\left(x^2-2x+\frac{7}{2}\right) \\ 2\left(x^2-2x+\frac{7}{2}+\left(-1\right)^2-\left(-1\right)^2\right) \\ 2\left(x-1\right)^2+5$$