# Chapter 6 Rational Exponents and Radical Functions - Cumulative Review Chapters 1-6 - Page 474: 28

$$\left(x+3\right)^2+7$$

#### Work Step by Step

Completing the square to put the equation in vertex form, we find: $$x^2+6x+16+3^2-3^2 \\ \left(x+3\right)^2+16-3^2 \\ \left(x+3\right)^2+7$$

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