## Algebra 2 (1st Edition)

$$x=0,\:x=2,\:x=-5$$
Using the rules of Algebra to solve, we obtain: $$x^3+3x^2-10x=0 \\ x\left(x-2\right)\left(x+5\right)=0 \\ x=0,\:x=2,\:x=-5$$