Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - Chapter Review - Page 321: 35



Work Step by Step

We complete the square to find: $$x^2-6x-15+\left(-3\right)^2-\left(-3\right)^2 \\ \left(x-3\right)^2-15-\left(-3\right)^2 \\ \left(x-3\right)^2-24 \\ \left(x-3\right)^2=24 \\ x=2\sqrt{6}+3,\:x=-2\sqrt{6}+3$$
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