Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - Chapter Review - Page 321: 39

Answer

$$x=-\frac{1}{3}$$

Work Step by Step

We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain: $$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$ $$x=\frac{-6\pm \sqrt{(6)^2-4(9)(1)}}{2(9)}$$ $$x=-\frac{1}{3}$$
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