Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - Chapter Review - Page 321: 37

Answer

$$x=\frac{\sqrt{13}-3}{2},\:x=\frac{-\sqrt{13}-3}{2}$$

Work Step by Step

We complete the square to find: $$x^2+3x-1+\left(\frac{3}{2}\right)^2-\left(\frac{3}{2}\right)^2 \\ \left(x+\frac{3}{2}\right)^2-1-\left(\frac{3}{2}\right)^2 \\ \left(x+\frac{3}{2}\right)^2-\frac{13}{4} \\ x=\frac{\sqrt{13}-3}{2},\:x=\frac{-\sqrt{13}-3}{2}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.