# Chapter 4 Quadratic Functions and Factoring - 4.5 Solve Quadratic Equations by Finding Square Roots - Guided Practice for Examples 2, 3 and 4 - Page 268: 19

The solutions are $2+\sqrt{\frac{40}{3}}$ and $2-\sqrt{\frac{40}{3}}$.

#### Work Step by Step

$3(x-2)^{2}=40\qquad$ ...divide each side with $3$. $(x-2)^{2}=\displaystyle \frac{40}{3}\qquad$ ...take square roots of each side. $\sqrt{(x-2)^{2}}=\sqrt{\frac{40}{3}}\qquad$ ...simplify. $x-2=\pm\sqrt{\frac{40}{3}}\qquad$ ...add $2$ to each side. $x-2+2=\pm\sqrt{\frac{40}{3}}+2\qquad$ ...simplify. $x=2\pm\sqrt{\frac{40}{3}}$

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