Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.5 Solve Quadratic Equations by Finding Square Roots - Guided Practice for Examples 2, 3 and 4 - Page 268: 19


The solutions are $2+\sqrt{\frac{40}{3}}$ and $2-\sqrt{\frac{40}{3}}$.

Work Step by Step

$ 3(x-2)^{2}=40\qquad$ ...divide each side with $3$. $(x-2)^{2}=\displaystyle \frac{40}{3}\qquad$ ...take square roots of each side. $\sqrt{(x-2)^{2}}=\sqrt{\frac{40}{3}}\qquad$ ...simplify. $ x-2=\pm\sqrt{\frac{40}{3}}\qquad$ ...add $2$ to each side. $ x-2+2=\pm\sqrt{\frac{40}{3}}+2\qquad$ ...simplify. $x=2\pm\sqrt{\frac{40}{3}}$
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