Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.5 Solve Quadratic Equations by Finding Square Roots - Guided Practice for Examples 2, 3 and 4 - Page 268: 18


The solutions are $6$ and $-6$.

Work Step by Step

$ z^{2}-7=29\qquad$ ...add $7$ to each side. $ z^{2}=29+7\qquad$ ...simplify. $ z^{2}=36\qquad$ ...take square roots of each side. $\sqrt{z^{2}}=\sqrt{36}\qquad$ ...simplify. ...When solving an equation of the form $x^{2}=s$ where $s>0$, we find both the positive and negative solutions. $z=\pm 6$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.