## Algebra 2 (1st Edition)

$\displaystyle \sqrt{\frac{9}{8}}=\frac{3}{2\sqrt{2}}$
$\sqrt{\frac{9}{8}}\qquad$ ...apply the Quotient Property:$\displaystyle \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}$ $=\displaystyle \frac{\sqrt{9}}{\sqrt{8}}\qquad$ ...evaluate the numerator ($\sqrt{9}=3$) and write $8$ as $4\cdot 2$. $=\displaystyle \frac{3}{\sqrt{4.2}}\qquad$ ...use the Product Property of square roots in the denominator:$\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$ $=\displaystyle \frac{3}{\sqrt{4}\cdot\sqrt{2}}\qquad$ ...evaluate part of the denominator ($\sqrt{4}=2$). $=\displaystyle \frac{3}{2\sqrt{2}}$