Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.5 Solve Quadratic Equations by Finding Square Roots - Guided Practice for Example 1 - Page 266: 6


$\displaystyle \sqrt{\frac{15}{4}}=\frac{\sqrt{15}}{2}$

Work Step by Step

$\sqrt{\frac{15}{4}}\qquad$ ...apply the Quotient Property:$\displaystyle \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}$ $=\displaystyle \frac{\sqrt{15}}{\sqrt{4}}\qquad$ ...evaluate the denominator ($\sqrt{4}=2$). $=\displaystyle \frac{\sqrt{15}}{2}$
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