## Algebra 2 (1st Edition)

$\sqrt{98}=7\sqrt{2}$
$\sqrt{98}=\sqrt{49\cdot 2}\qquad$ ...write $49$ as $7^{2}$. $=\sqrt{7^{2}\cdot 2}\qquad$ ...use the Product Property of square roots:$\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$ $=\sqrt{7^{2}}\cdot\sqrt{2}\qquad$ ...simplify. $=7\sqrt{2}$