Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.5 Solve Quadratic Equations by Finding Square Roots - Guided Practice for Example 1 - Page 266: 2

Answer

$\sqrt{98}=7\sqrt{2}$

Work Step by Step

$\sqrt{98}=\sqrt{49\cdot 2}\qquad$ ...write $49$ as $7^{2}$. $=\sqrt{7^{2}\cdot 2}\qquad$ ...use the Product Property of square roots:$\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$ $=\sqrt{7^{2}}\cdot\sqrt{2}\qquad$ ...simplify. $=7\sqrt{2}$
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