Answer
$\sqrt{8}\cdot\sqrt{28}=4\sqrt{14}$
Work Step by Step
$\sqrt{8}\cdot\sqrt{28}\qquad$ ...write $28$ as $4\cdot 7$.
$=\sqrt{8}\cdot\sqrt{4\cdot 7}\qquad$ ...write $8$ as $4\cdot 2$
$=\sqrt{4\cdot 2}\cdot\sqrt{4\cdot 7}\qquad$ ...use the Product Property of square roots:$\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$
$=\sqrt{4}\cdot\sqrt{2}\cdot\sqrt{4}\cdot\sqrt{7}\qquad$ ...simplify.
$=4\cdot\sqrt{2}\cdot\sqrt{7}\qquad$ ...use the Product Property of square roots:$\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$
$=4\sqrt{2\cdot 7}\qquad$ ...simplify.
$=4\sqrt{14}$
